3.7.7 \(\int x^2 (a+b x)^{3/2} (c+d x)^{3/2} \, dx\) [607]

Optimal. Leaf size=349 \[ \frac {(b c-a d)^3 \left (4 a b c d-7 (b c+a d)^2\right ) \sqrt {a+b x} \sqrt {c+d x}}{512 b^4 d^4}-\frac {(b c-a d)^2 \left (4 a b c d-7 (b c+a d)^2\right ) (a+b x)^{3/2} \sqrt {c+d x}}{768 b^4 d^3}-\frac {(b c-a d) \left (4 a b c d-7 (b c+a d)^2\right ) (a+b x)^{5/2} \sqrt {c+d x}}{192 b^4 d^2}-\frac {\left (4 a b c d-7 (b c+a d)^2\right ) (a+b x)^{5/2} (c+d x)^{3/2}}{96 b^3 d^2}-\frac {7 (b c+a d) (a+b x)^{5/2} (c+d x)^{5/2}}{60 b^2 d^2}+\frac {x (a+b x)^{5/2} (c+d x)^{5/2}}{6 b d}-\frac {(b c-a d)^4 \left (4 a b c d-7 (b c+a d)^2\right ) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{512 b^{9/2} d^{9/2}} \]

[Out]

-1/96*(4*a*b*c*d-7*(a*d+b*c)^2)*(b*x+a)^(5/2)*(d*x+c)^(3/2)/b^3/d^2-7/60*(a*d+b*c)*(b*x+a)^(5/2)*(d*x+c)^(5/2)
/b^2/d^2+1/6*x*(b*x+a)^(5/2)*(d*x+c)^(5/2)/b/d-1/512*(-a*d+b*c)^4*(4*a*b*c*d-7*(a*d+b*c)^2)*arctanh(d^(1/2)*(b
*x+a)^(1/2)/b^(1/2)/(d*x+c)^(1/2))/b^(9/2)/d^(9/2)-1/768*(-a*d+b*c)^2*(4*a*b*c*d-7*(a*d+b*c)^2)*(b*x+a)^(3/2)*
(d*x+c)^(1/2)/b^4/d^3-1/192*(-a*d+b*c)*(4*a*b*c*d-7*(a*d+b*c)^2)*(b*x+a)^(5/2)*(d*x+c)^(1/2)/b^4/d^2+1/512*(-a
*d+b*c)^3*(4*a*b*c*d-7*(a*d+b*c)^2)*(b*x+a)^(1/2)*(d*x+c)^(1/2)/b^4/d^4

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Rubi [A]
time = 0.21, antiderivative size = 349, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 6, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.273, Rules used = {92, 81, 52, 65, 223, 212} \begin {gather*} -\frac {\left (4 a b c d-7 (a d+b c)^2\right ) (b c-a d)^4 \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{512 b^{9/2} d^{9/2}}+\frac {\sqrt {a+b x} \sqrt {c+d x} \left (4 a b c d-7 (a d+b c)^2\right ) (b c-a d)^3}{512 b^4 d^4}-\frac {(a+b x)^{3/2} \sqrt {c+d x} \left (4 a b c d-7 (a d+b c)^2\right ) (b c-a d)^2}{768 b^4 d^3}-\frac {(a+b x)^{5/2} \sqrt {c+d x} \left (4 a b c d-7 (a d+b c)^2\right ) (b c-a d)}{192 b^4 d^2}-\frac {(a+b x)^{5/2} (c+d x)^{3/2} \left (4 a b c d-7 (a d+b c)^2\right )}{96 b^3 d^2}-\frac {7 (a+b x)^{5/2} (c+d x)^{5/2} (a d+b c)}{60 b^2 d^2}+\frac {x (a+b x)^{5/2} (c+d x)^{5/2}}{6 b d} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^2*(a + b*x)^(3/2)*(c + d*x)^(3/2),x]

[Out]

((b*c - a*d)^3*(4*a*b*c*d - 7*(b*c + a*d)^2)*Sqrt[a + b*x]*Sqrt[c + d*x])/(512*b^4*d^4) - ((b*c - a*d)^2*(4*a*
b*c*d - 7*(b*c + a*d)^2)*(a + b*x)^(3/2)*Sqrt[c + d*x])/(768*b^4*d^3) - ((b*c - a*d)*(4*a*b*c*d - 7*(b*c + a*d
)^2)*(a + b*x)^(5/2)*Sqrt[c + d*x])/(192*b^4*d^2) - ((4*a*b*c*d - 7*(b*c + a*d)^2)*(a + b*x)^(5/2)*(c + d*x)^(
3/2))/(96*b^3*d^2) - (7*(b*c + a*d)*(a + b*x)^(5/2)*(c + d*x)^(5/2))/(60*b^2*d^2) + (x*(a + b*x)^(5/2)*(c + d*
x)^(5/2))/(6*b*d) - ((b*c - a*d)^4*(4*a*b*c*d - 7*(b*c + a*d)^2)*ArcTanh[(Sqrt[d]*Sqrt[a + b*x])/(Sqrt[b]*Sqrt
[c + d*x])])/(512*b^(9/2)*d^(9/2))

Rule 52

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^n/(b*(
m + n + 1))), x] + Dist[n*((b*c - a*d)/(b*(m + n + 1))), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 65

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 81

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[b*(c + d*x)^
(n + 1)*((e + f*x)^(p + 1)/(d*f*(n + p + 2))), x] + Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1) + c*f*(p + 1)))/(
d*f*(n + p + 2)), Int[(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && NeQ[n + p + 2,
0]

Rule 92

Int[((a_.) + (b_.)*(x_))^2*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[b*(a + b*x
)*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/(d*f*(n + p + 3))), x] + Dist[1/(d*f*(n + p + 3)), Int[(c + d*x)^n*(e +
f*x)^p*Simp[a^2*d*f*(n + p + 3) - b*(b*c*e + a*(d*e*(n + 1) + c*f*(p + 1))) + b*(a*d*f*(n + p + 4) - b*(d*e*(
n + 2) + c*f*(p + 2)))*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && NeQ[n + p + 3, 0]

Rule 212

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))*ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 223

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Subst[Int[1/(1 - b*x^2), x], x, x/Sqrt[a + b*x^2]] /; FreeQ[{a,
b}, x] &&  !GtQ[a, 0]

Rubi steps

\begin {align*} \int x^2 (a+b x)^{3/2} (c+d x)^{3/2} \, dx &=\frac {x (a+b x)^{5/2} (c+d x)^{5/2}}{6 b d}+\frac {\int (a+b x)^{3/2} (c+d x)^{3/2} \left (-a c-\frac {7}{2} (b c+a d) x\right ) \, dx}{6 b d}\\ &=-\frac {7 (b c+a d) (a+b x)^{5/2} (c+d x)^{5/2}}{60 b^2 d^2}+\frac {x (a+b x)^{5/2} (c+d x)^{5/2}}{6 b d}-\frac {\left (4 a b c d-7 (b c+a d)^2\right ) \int (a+b x)^{3/2} (c+d x)^{3/2} \, dx}{24 b^2 d^2}\\ &=-\frac {\left (4 a b c d-7 (b c+a d)^2\right ) (a+b x)^{5/2} (c+d x)^{3/2}}{96 b^3 d^2}-\frac {7 (b c+a d) (a+b x)^{5/2} (c+d x)^{5/2}}{60 b^2 d^2}+\frac {x (a+b x)^{5/2} (c+d x)^{5/2}}{6 b d}-\frac {\left ((b c-a d) \left (4 a b c d-7 (b c+a d)^2\right )\right ) \int (a+b x)^{3/2} \sqrt {c+d x} \, dx}{64 b^3 d^2}\\ &=-\frac {(b c-a d) \left (4 a b c d-7 (b c+a d)^2\right ) (a+b x)^{5/2} \sqrt {c+d x}}{192 b^4 d^2}-\frac {\left (4 a b c d-7 (b c+a d)^2\right ) (a+b x)^{5/2} (c+d x)^{3/2}}{96 b^3 d^2}-\frac {7 (b c+a d) (a+b x)^{5/2} (c+d x)^{5/2}}{60 b^2 d^2}+\frac {x (a+b x)^{5/2} (c+d x)^{5/2}}{6 b d}-\frac {\left ((b c-a d)^2 \left (4 a b c d-7 (b c+a d)^2\right )\right ) \int \frac {(a+b x)^{3/2}}{\sqrt {c+d x}} \, dx}{384 b^4 d^2}\\ &=-\frac {(b c-a d)^2 \left (4 a b c d-7 (b c+a d)^2\right ) (a+b x)^{3/2} \sqrt {c+d x}}{768 b^4 d^3}-\frac {(b c-a d) \left (4 a b c d-7 (b c+a d)^2\right ) (a+b x)^{5/2} \sqrt {c+d x}}{192 b^4 d^2}-\frac {\left (4 a b c d-7 (b c+a d)^2\right ) (a+b x)^{5/2} (c+d x)^{3/2}}{96 b^3 d^2}-\frac {7 (b c+a d) (a+b x)^{5/2} (c+d x)^{5/2}}{60 b^2 d^2}+\frac {x (a+b x)^{5/2} (c+d x)^{5/2}}{6 b d}+\frac {\left ((b c-a d)^3 \left (4 a b c d-7 (b c+a d)^2\right )\right ) \int \frac {\sqrt {a+b x}}{\sqrt {c+d x}} \, dx}{512 b^4 d^3}\\ &=\frac {(b c-a d)^3 \left (4 a b c d-7 (b c+a d)^2\right ) \sqrt {a+b x} \sqrt {c+d x}}{512 b^4 d^4}-\frac {(b c-a d)^2 \left (4 a b c d-7 (b c+a d)^2\right ) (a+b x)^{3/2} \sqrt {c+d x}}{768 b^4 d^3}-\frac {(b c-a d) \left (4 a b c d-7 (b c+a d)^2\right ) (a+b x)^{5/2} \sqrt {c+d x}}{192 b^4 d^2}-\frac {\left (4 a b c d-7 (b c+a d)^2\right ) (a+b x)^{5/2} (c+d x)^{3/2}}{96 b^3 d^2}-\frac {7 (b c+a d) (a+b x)^{5/2} (c+d x)^{5/2}}{60 b^2 d^2}+\frac {x (a+b x)^{5/2} (c+d x)^{5/2}}{6 b d}-\frac {\left ((b c-a d)^4 \left (4 a b c d-7 (b c+a d)^2\right )\right ) \int \frac {1}{\sqrt {a+b x} \sqrt {c+d x}} \, dx}{1024 b^4 d^4}\\ &=\frac {(b c-a d)^3 \left (4 a b c d-7 (b c+a d)^2\right ) \sqrt {a+b x} \sqrt {c+d x}}{512 b^4 d^4}-\frac {(b c-a d)^2 \left (4 a b c d-7 (b c+a d)^2\right ) (a+b x)^{3/2} \sqrt {c+d x}}{768 b^4 d^3}-\frac {(b c-a d) \left (4 a b c d-7 (b c+a d)^2\right ) (a+b x)^{5/2} \sqrt {c+d x}}{192 b^4 d^2}-\frac {\left (4 a b c d-7 (b c+a d)^2\right ) (a+b x)^{5/2} (c+d x)^{3/2}}{96 b^3 d^2}-\frac {7 (b c+a d) (a+b x)^{5/2} (c+d x)^{5/2}}{60 b^2 d^2}+\frac {x (a+b x)^{5/2} (c+d x)^{5/2}}{6 b d}-\frac {\left ((b c-a d)^4 \left (4 a b c d-7 (b c+a d)^2\right )\right ) \text {Subst}\left (\int \frac {1}{\sqrt {c-\frac {a d}{b}+\frac {d x^2}{b}}} \, dx,x,\sqrt {a+b x}\right )}{512 b^5 d^4}\\ &=\frac {(b c-a d)^3 \left (4 a b c d-7 (b c+a d)^2\right ) \sqrt {a+b x} \sqrt {c+d x}}{512 b^4 d^4}-\frac {(b c-a d)^2 \left (4 a b c d-7 (b c+a d)^2\right ) (a+b x)^{3/2} \sqrt {c+d x}}{768 b^4 d^3}-\frac {(b c-a d) \left (4 a b c d-7 (b c+a d)^2\right ) (a+b x)^{5/2} \sqrt {c+d x}}{192 b^4 d^2}-\frac {\left (4 a b c d-7 (b c+a d)^2\right ) (a+b x)^{5/2} (c+d x)^{3/2}}{96 b^3 d^2}-\frac {7 (b c+a d) (a+b x)^{5/2} (c+d x)^{5/2}}{60 b^2 d^2}+\frac {x (a+b x)^{5/2} (c+d x)^{5/2}}{6 b d}-\frac {\left ((b c-a d)^4 \left (4 a b c d-7 (b c+a d)^2\right )\right ) \text {Subst}\left (\int \frac {1}{1-\frac {d x^2}{b}} \, dx,x,\frac {\sqrt {a+b x}}{\sqrt {c+d x}}\right )}{512 b^5 d^4}\\ &=\frac {(b c-a d)^3 \left (4 a b c d-7 (b c+a d)^2\right ) \sqrt {a+b x} \sqrt {c+d x}}{512 b^4 d^4}-\frac {(b c-a d)^2 \left (4 a b c d-7 (b c+a d)^2\right ) (a+b x)^{3/2} \sqrt {c+d x}}{768 b^4 d^3}-\frac {(b c-a d) \left (4 a b c d-7 (b c+a d)^2\right ) (a+b x)^{5/2} \sqrt {c+d x}}{192 b^4 d^2}-\frac {\left (4 a b c d-7 (b c+a d)^2\right ) (a+b x)^{5/2} (c+d x)^{3/2}}{96 b^3 d^2}-\frac {7 (b c+a d) (a+b x)^{5/2} (c+d x)^{5/2}}{60 b^2 d^2}+\frac {x (a+b x)^{5/2} (c+d x)^{5/2}}{6 b d}-\frac {(b c-a d)^4 \left (4 a b c d-7 (b c+a d)^2\right ) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{512 b^{9/2} d^{9/2}}\\ \end {align*}

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Mathematica [A]
time = 0.75, size = 306, normalized size = 0.88 \begin {gather*} \frac {\sqrt {a+b x} \sqrt {c+d x} \left (-105 a^5 d^5+5 a^4 b d^4 (47 c+14 d x)-2 a^3 b^2 d^3 \left (33 c^2+76 c d x+28 d^2 x^2\right )+6 a^2 b^3 d^2 \left (-11 c^3+6 c^2 d x+20 c d^2 x^2+8 d^3 x^3\right )+a b^4 d \left (235 c^4-152 c^3 d x+120 c^2 d^2 x^2+2336 c d^3 x^3+1664 d^4 x^4\right )+b^5 \left (-105 c^5+70 c^4 d x-56 c^3 d^2 x^2+48 c^2 d^3 x^3+1664 c d^4 x^4+1280 d^5 x^5\right )\right )}{7680 b^4 d^4}+\frac {(b c-a d)^4 \left (7 b^2 c^2+10 a b c d+7 a^2 d^2\right ) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {d} \sqrt {a+b x}}\right )}{512 b^{9/2} d^{9/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^2*(a + b*x)^(3/2)*(c + d*x)^(3/2),x]

[Out]

(Sqrt[a + b*x]*Sqrt[c + d*x]*(-105*a^5*d^5 + 5*a^4*b*d^4*(47*c + 14*d*x) - 2*a^3*b^2*d^3*(33*c^2 + 76*c*d*x +
28*d^2*x^2) + 6*a^2*b^3*d^2*(-11*c^3 + 6*c^2*d*x + 20*c*d^2*x^2 + 8*d^3*x^3) + a*b^4*d*(235*c^4 - 152*c^3*d*x
+ 120*c^2*d^2*x^2 + 2336*c*d^3*x^3 + 1664*d^4*x^4) + b^5*(-105*c^5 + 70*c^4*d*x - 56*c^3*d^2*x^2 + 48*c^2*d^3*
x^3 + 1664*c*d^4*x^4 + 1280*d^5*x^5)))/(7680*b^4*d^4) + ((b*c - a*d)^4*(7*b^2*c^2 + 10*a*b*c*d + 7*a^2*d^2)*Ar
cTanh[(Sqrt[b]*Sqrt[c + d*x])/(Sqrt[d]*Sqrt[a + b*x])])/(512*b^(9/2)*d^(9/2))

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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(1036\) vs. \(2(299)=598\).
time = 0.07, size = 1037, normalized size = 2.97

method	result	size
default	\(\frac {\sqrt {b x +a}\, \sqrt {d x +c}\, \left (96 a^{2} b^{3} d^{5} x^{3} \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, \sqrt {b d}+96 b^{5} c^{2} d^{3} x^{3} \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, \sqrt {b d}-112 a^{3} b^{2} d^{5} x^{2} \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, \sqrt {b d}-112 b^{5} c^{3} d^{2} x^{2} \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, \sqrt {b d}+3328 a \,b^{4} d^{5} x^{4} \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, \sqrt {b d}+3328 b^{5} c \,d^{4} x^{4} \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, \sqrt {b d}-210 \sqrt {b d}\, \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, a^{5} d^{5}-210 \sqrt {b d}\, \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, b^{5} c^{5}+140 \sqrt {b d}\, \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, a^{4} b \,d^{5} x +140 \sqrt {b d}\, \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, b^{5} c^{4} d x +470 \sqrt {b d}\, \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, a^{4} b c \,d^{4}-132 \sqrt {b d}\, \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, a^{3} b^{2} c^{2} d^{3}-132 \sqrt {b d}\, \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, a^{2} b^{3} c^{3} d^{2}+470 \sqrt {b d}\, \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, a \,b^{4} c^{4} d -304 \sqrt {b d}\, \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, a^{3} b^{2} c \,d^{4} x +72 \sqrt {b d}\, \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, a^{2} b^{3} c^{2} d^{3} x -304 \sqrt {b d}\, \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, a \,b^{4} c^{3} d^{2} x +105 \ln \left (\frac {2 b d x +2 \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) a^{6} d^{6}+105 \ln \left (\frac {2 b d x +2 \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) b^{6} c^{6}-270 \ln \left (\frac {2 b d x +2 \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) a^{5} b c \,d^{5}+2560 b^{5} d^{5} x^{5} \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, \sqrt {b d}+135 \ln \left (\frac {2 b d x +2 \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) a^{4} b^{2} c^{2} d^{4}+60 \ln \left (\frac {2 b d x +2 \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) a^{3} b^{3} c^{3} d^{3}+135 \ln \left (\frac {2 b d x +2 \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) a^{2} b^{4} c^{4} d^{2}-270 \ln \left (\frac {2 b d x +2 \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) a \,b^{5} c^{5} d +4672 a \,b^{4} c \,d^{4} x^{3} \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, \sqrt {b d}+240 a^{2} b^{3} c \,d^{4} x^{2} \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, \sqrt {b d}+240 a \,b^{4} c^{2} d^{3} x^{2} \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, \sqrt {b d}\right )}{15360 b^{4} d^{4} \sqrt {\left (d x +c \right ) \left (b x +a \right )}\, \sqrt {b d}}\)	\(1037\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*(b*x+a)^(3/2)*(d*x+c)^(3/2),x,method=_RETURNVERBOSE)

[Out]

1/15360*(b*x+a)^(1/2)*(d*x+c)^(1/2)*(96*a^2*b^3*d^5*x^3*((d*x+c)*(b*x+a))^(1/2)*(b*d)^(1/2)+96*b^5*c^2*d^3*x^3
*((d*x+c)*(b*x+a))^(1/2)*(b*d)^(1/2)-112*a^3*b^2*d^5*x^2*((d*x+c)*(b*x+a))^(1/2)*(b*d)^(1/2)-112*b^5*c^3*d^2*x
^2*((d*x+c)*(b*x+a))^(1/2)*(b*d)^(1/2)+3328*a*b^4*d^5*x^4*((d*x+c)*(b*x+a))^(1/2)*(b*d)^(1/2)+3328*b^5*c*d^4*x
^4*((d*x+c)*(b*x+a))^(1/2)*(b*d)^(1/2)-210*(b*d)^(1/2)*((d*x+c)*(b*x+a))^(1/2)*a^5*d^5-210*(b*d)^(1/2)*((d*x+c
)*(b*x+a))^(1/2)*b^5*c^5+140*(b*d)^(1/2)*((d*x+c)*(b*x+a))^(1/2)*a^4*b*d^5*x+140*(b*d)^(1/2)*((d*x+c)*(b*x+a))
^(1/2)*b^5*c^4*d*x+470*(b*d)^(1/2)*((d*x+c)*(b*x+a))^(1/2)*a^4*b*c*d^4-132*(b*d)^(1/2)*((d*x+c)*(b*x+a))^(1/2)
*a^3*b^2*c^2*d^3-132*(b*d)^(1/2)*((d*x+c)*(b*x+a))^(1/2)*a^2*b^3*c^3*d^2+470*(b*d)^(1/2)*((d*x+c)*(b*x+a))^(1/
2)*a*b^4*c^4*d-304*(b*d)^(1/2)*((d*x+c)*(b*x+a))^(1/2)*a^3*b^2*c*d^4*x+72*(b*d)^(1/2)*((d*x+c)*(b*x+a))^(1/2)*
a^2*b^3*c^2*d^3*x-304*(b*d)^(1/2)*((d*x+c)*(b*x+a))^(1/2)*a*b^4*c^3*d^2*x+105*ln(1/2*(2*b*d*x+2*((d*x+c)*(b*x+
a))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*a^6*d^6+105*ln(1/2*(2*b*d*x+2*((d*x+c)*(b*x+a))^(1/2)*(b*d)^(1/2)+
a*d+b*c)/(b*d)^(1/2))*b^6*c^6-270*ln(1/2*(2*b*d*x+2*((d*x+c)*(b*x+a))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*
a^5*b*c*d^5+2560*b^5*d^5*x^5*((d*x+c)*(b*x+a))^(1/2)*(b*d)^(1/2)+135*ln(1/2*(2*b*d*x+2*((d*x+c)*(b*x+a))^(1/2)
*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*a^4*b^2*c^2*d^4+60*ln(1/2*(2*b*d*x+2*((d*x+c)*(b*x+a))^(1/2)*(b*d)^(1/2)+a*
d+b*c)/(b*d)^(1/2))*a^3*b^3*c^3*d^3+135*ln(1/2*(2*b*d*x+2*((d*x+c)*(b*x+a))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(
1/2))*a^2*b^4*c^4*d^2-270*ln(1/2*(2*b*d*x+2*((d*x+c)*(b*x+a))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*a*b^5*c^
5*d+4672*a*b^4*c*d^4*x^3*((d*x+c)*(b*x+a))^(1/2)*(b*d)^(1/2)+240*a^2*b^3*c*d^4*x^2*((d*x+c)*(b*x+a))^(1/2)*(b*
d)^(1/2)+240*a*b^4*c^2*d^3*x^2*((d*x+c)*(b*x+a))^(1/2)*(b*d)^(1/2))/b^4/d^4/((d*x+c)*(b*x+a))^(1/2)/(b*d)^(1/2
)

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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(b*x+a)^(3/2)*(d*x+c)^(3/2),x, algorithm="maxima")

[Out]

Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'a
ssume' command before evaluation *may* help (example of legal syntax is 'assume(a*d-b*c>0)', see `assume?` for
more detail

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Fricas [A]
time = 0.91, size = 890, normalized size = 2.55 \begin {gather*} \left [\frac {15 \, {\left (7 \, b^{6} c^{6} - 18 \, a b^{5} c^{5} d + 9 \, a^{2} b^{4} c^{4} d^{2} + 4 \, a^{3} b^{3} c^{3} d^{3} + 9 \, a^{4} b^{2} c^{2} d^{4} - 18 \, a^{5} b c d^{5} + 7 \, a^{6} d^{6}\right )} \sqrt {b d} \log \left (8 \, b^{2} d^{2} x^{2} + b^{2} c^{2} + 6 \, a b c d + a^{2} d^{2} + 4 \, {\left (2 \, b d x + b c + a d\right )} \sqrt {b d} \sqrt {b x + a} \sqrt {d x + c} + 8 \, {\left (b^{2} c d + a b d^{2}\right )} x\right ) + 4 \, {\left (1280 \, b^{6} d^{6} x^{5} - 105 \, b^{6} c^{5} d + 235 \, a b^{5} c^{4} d^{2} - 66 \, a^{2} b^{4} c^{3} d^{3} - 66 \, a^{3} b^{3} c^{2} d^{4} + 235 \, a^{4} b^{2} c d^{5} - 105 \, a^{5} b d^{6} + 1664 \, {\left (b^{6} c d^{5} + a b^{5} d^{6}\right )} x^{4} + 16 \, {\left (3 \, b^{6} c^{2} d^{4} + 146 \, a b^{5} c d^{5} + 3 \, a^{2} b^{4} d^{6}\right )} x^{3} - 8 \, {\left (7 \, b^{6} c^{3} d^{3} - 15 \, a b^{5} c^{2} d^{4} - 15 \, a^{2} b^{4} c d^{5} + 7 \, a^{3} b^{3} d^{6}\right )} x^{2} + 2 \, {\left (35 \, b^{6} c^{4} d^{2} - 76 \, a b^{5} c^{3} d^{3} + 18 \, a^{2} b^{4} c^{2} d^{4} - 76 \, a^{3} b^{3} c d^{5} + 35 \, a^{4} b^{2} d^{6}\right )} x\right )} \sqrt {b x + a} \sqrt {d x + c}}{30720 \, b^{5} d^{5}}, -\frac {15 \, {\left (7 \, b^{6} c^{6} - 18 \, a b^{5} c^{5} d + 9 \, a^{2} b^{4} c^{4} d^{2} + 4 \, a^{3} b^{3} c^{3} d^{3} + 9 \, a^{4} b^{2} c^{2} d^{4} - 18 \, a^{5} b c d^{5} + 7 \, a^{6} d^{6}\right )} \sqrt {-b d} \arctan \left (\frac {{\left (2 \, b d x + b c + a d\right )} \sqrt {-b d} \sqrt {b x + a} \sqrt {d x + c}}{2 \, {\left (b^{2} d^{2} x^{2} + a b c d + {\left (b^{2} c d + a b d^{2}\right )} x\right )}}\right ) - 2 \, {\left (1280 \, b^{6} d^{6} x^{5} - 105 \, b^{6} c^{5} d + 235 \, a b^{5} c^{4} d^{2} - 66 \, a^{2} b^{4} c^{3} d^{3} - 66 \, a^{3} b^{3} c^{2} d^{4} + 235 \, a^{4} b^{2} c d^{5} - 105 \, a^{5} b d^{6} + 1664 \, {\left (b^{6} c d^{5} + a b^{5} d^{6}\right )} x^{4} + 16 \, {\left (3 \, b^{6} c^{2} d^{4} + 146 \, a b^{5} c d^{5} + 3 \, a^{2} b^{4} d^{6}\right )} x^{3} - 8 \, {\left (7 \, b^{6} c^{3} d^{3} - 15 \, a b^{5} c^{2} d^{4} - 15 \, a^{2} b^{4} c d^{5} + 7 \, a^{3} b^{3} d^{6}\right )} x^{2} + 2 \, {\left (35 \, b^{6} c^{4} d^{2} - 76 \, a b^{5} c^{3} d^{3} + 18 \, a^{2} b^{4} c^{2} d^{4} - 76 \, a^{3} b^{3} c d^{5} + 35 \, a^{4} b^{2} d^{6}\right )} x\right )} \sqrt {b x + a} \sqrt {d x + c}}{15360 \, b^{5} d^{5}}\right ] \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(b*x+a)^(3/2)*(d*x+c)^(3/2),x, algorithm="fricas")

[Out]

[1/30720*(15*(7*b^6*c^6 - 18*a*b^5*c^5*d + 9*a^2*b^4*c^4*d^2 + 4*a^3*b^3*c^3*d^3 + 9*a^4*b^2*c^2*d^4 - 18*a^5*
b*c*d^5 + 7*a^6*d^6)*sqrt(b*d)*log(8*b^2*d^2*x^2 + b^2*c^2 + 6*a*b*c*d + a^2*d^2 + 4*(2*b*d*x + b*c + a*d)*sqr
t(b*d)*sqrt(b*x + a)*sqrt(d*x + c) + 8*(b^2*c*d + a*b*d^2)*x) + 4*(1280*b^6*d^6*x^5 - 105*b^6*c^5*d + 235*a*b^
5*c^4*d^2 - 66*a^2*b^4*c^3*d^3 - 66*a^3*b^3*c^2*d^4 + 235*a^4*b^2*c*d^5 - 105*a^5*b*d^6 + 1664*(b^6*c*d^5 + a*
b^5*d^6)*x^4 + 16*(3*b^6*c^2*d^4 + 146*a*b^5*c*d^5 + 3*a^2*b^4*d^6)*x^3 - 8*(7*b^6*c^3*d^3 - 15*a*b^5*c^2*d^4
- 15*a^2*b^4*c*d^5 + 7*a^3*b^3*d^6)*x^2 + 2*(35*b^6*c^4*d^2 - 76*a*b^5*c^3*d^3 + 18*a^2*b^4*c^2*d^4 - 76*a^3*b
^3*c*d^5 + 35*a^4*b^2*d^6)*x)*sqrt(b*x + a)*sqrt(d*x + c))/(b^5*d^5), -1/15360*(15*(7*b^6*c^6 - 18*a*b^5*c^5*d
+ 9*a^2*b^4*c^4*d^2 + 4*a^3*b^3*c^3*d^3 + 9*a^4*b^2*c^2*d^4 - 18*a^5*b*c*d^5 + 7*a^6*d^6)*sqrt(-b*d)*arctan(1
/2*(2*b*d*x + b*c + a*d)*sqrt(-b*d)*sqrt(b*x + a)*sqrt(d*x + c)/(b^2*d^2*x^2 + a*b*c*d + (b^2*c*d + a*b*d^2)*x
)) - 2*(1280*b^6*d^6*x^5 - 105*b^6*c^5*d + 235*a*b^5*c^4*d^2 - 66*a^2*b^4*c^3*d^3 - 66*a^3*b^3*c^2*d^4 + 235*a
^4*b^2*c*d^5 - 105*a^5*b*d^6 + 1664*(b^6*c*d^5 + a*b^5*d^6)*x^4 + 16*(3*b^6*c^2*d^4 + 146*a*b^5*c*d^5 + 3*a^2*
b^4*d^6)*x^3 - 8*(7*b^6*c^3*d^3 - 15*a*b^5*c^2*d^4 - 15*a^2*b^4*c*d^5 + 7*a^3*b^3*d^6)*x^2 + 2*(35*b^6*c^4*d^2
- 76*a*b^5*c^3*d^3 + 18*a^2*b^4*c^2*d^4 - 76*a^3*b^3*c*d^5 + 35*a^4*b^2*d^6)*x)*sqrt(b*x + a)*sqrt(d*x + c))/
(b^5*d^5)]

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x^{2} \left (a + b x\right )^{\frac {3}{2}} \left (c + d x\right )^{\frac {3}{2}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2*(b*x+a)**(3/2)*(d*x+c)**(3/2),x)

[Out]

Integral(x**2*(a + b*x)**(3/2)*(c + d*x)**(3/2), x)

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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 2032 vs. \(2 (299) = 598\).
time = 1.42, size = 2032, normalized size = 5.82 \begin {gather*} \text {Too large to display} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(b*x+a)^(3/2)*(d*x+c)^(3/2),x, algorithm="giac")

[Out]

1/7680*(4*(sqrt(b^2*c + (b*x + a)*b*d - a*b*d)*(2*(4*(b*x + a)*(6*(b*x + a)*(8*(b*x + a)/b^4 + (b^20*c*d^7 - 4
1*a*b^19*d^8)/(b^23*d^8)) - (7*b^21*c^2*d^6 + 26*a*b^20*c*d^7 - 513*a^2*b^19*d^8)/(b^23*d^8)) + 5*(7*b^22*c^3*
d^5 + 19*a*b^21*c^2*d^6 + 37*a^2*b^20*c*d^7 - 447*a^3*b^19*d^8)/(b^23*d^8))*(b*x + a) - 15*(7*b^23*c^4*d^4 + 1
2*a*b^22*c^3*d^5 + 18*a^2*b^21*c^2*d^6 + 28*a^3*b^20*c*d^7 - 193*a^4*b^19*d^8)/(b^23*d^8))*sqrt(b*x + a) - 15*
(7*b^5*c^5 + 5*a*b^4*c^4*d + 6*a^2*b^3*c^3*d^2 + 10*a^3*b^2*c^2*d^3 + 35*a^4*b*c*d^4 - 63*a^5*d^5)*log(abs(-sq
rt(b*d)*sqrt(b*x + a) + sqrt(b^2*c + (b*x + a)*b*d - a*b*d)))/(sqrt(b*d)*b^3*d^4))*c*abs(b) + 320*(sqrt(b^2*c
+ (b*x + a)*b*d - a*b*d)*sqrt(b*x + a)*(2*(b*x + a)*(4*(b*x + a)/b^2 + (b^6*c*d^3 - 13*a*b^5*d^4)/(b^7*d^4)) -
3*(b^7*c^2*d^2 + 2*a*b^6*c*d^3 - 11*a^2*b^5*d^4)/(b^7*d^4)) - 3*(b^3*c^3 + a*b^2*c^2*d + 3*a^2*b*c*d^2 - 5*a^
3*d^3)*log(abs(-sqrt(b*d)*sqrt(b*x + a) + sqrt(b^2*c + (b*x + a)*b*d - a*b*d)))/(sqrt(b*d)*b*d^2))*a^2*c*abs(b
)/b^2 + 80*(sqrt(b^2*c + (b*x + a)*b*d - a*b*d)*(2*(b*x + a)*(4*(b*x + a)*(6*(b*x + a)/b^3 + (b^12*c*d^5 - 25*
a*b^11*d^6)/(b^14*d^6)) - (5*b^13*c^2*d^4 + 14*a*b^12*c*d^5 - 163*a^2*b^11*d^6)/(b^14*d^6)) + 3*(5*b^14*c^3*d^
3 + 9*a*b^13*c^2*d^4 + 15*a^2*b^12*c*d^5 - 93*a^3*b^11*d^6)/(b^14*d^6))*sqrt(b*x + a) + 3*(5*b^4*c^4 + 4*a*b^3
*c^3*d + 6*a^2*b^2*c^2*d^2 + 20*a^3*b*c*d^3 - 35*a^4*d^4)*log(abs(-sqrt(b*d)*sqrt(b*x + a) + sqrt(b^2*c + (b*x
+ a)*b*d - a*b*d)))/(sqrt(b*d)*b^2*d^3))*a*c*abs(b)/b + (sqrt(b^2*c + (b*x + a)*b*d - a*b*d)*(2*(4*(2*(b*x +
a)*(8*(b*x + a)*(10*(b*x + a)/b^5 + (b^30*c*d^9 - 61*a*b^29*d^10)/(b^34*d^10)) - 3*(3*b^31*c^2*d^8 + 14*a*b^30
*c*d^9 - 417*a^2*b^29*d^10)/(b^34*d^10)) + (21*b^32*c^3*d^7 + 77*a*b^31*c^2*d^8 + 183*a^2*b^30*c*d^9 - 3481*a^
3*b^29*d^10)/(b^34*d^10))*(b*x + a) - 5*(21*b^33*c^4*d^6 + 56*a*b^32*c^3*d^7 + 106*a^2*b^31*c^2*d^8 + 176*a^3*
b^30*c*d^9 - 2279*a^4*b^29*d^10)/(b^34*d^10))*(b*x + a) + 15*(21*b^34*c^5*d^5 + 35*a*b^33*c^4*d^6 + 50*a^2*b^3
2*c^3*d^7 + 70*a^3*b^31*c^2*d^8 + 105*a^4*b^30*c*d^9 - 793*a^5*b^29*d^10)/(b^34*d^10))*sqrt(b*x + a) + 15*(21*
b^6*c^6 + 14*a*b^5*c^5*d + 15*a^2*b^4*c^4*d^2 + 20*a^3*b^3*c^3*d^3 + 35*a^4*b^2*c^2*d^4 + 126*a^5*b*c*d^5 - 23
1*a^6*d^6)*log(abs(-sqrt(b*d)*sqrt(b*x + a) + sqrt(b^2*c + (b*x + a)*b*d - a*b*d)))/(sqrt(b*d)*b^4*d^5))*d*abs
(b) + 40*(sqrt(b^2*c + (b*x + a)*b*d - a*b*d)*(2*(b*x + a)*(4*(b*x + a)*(6*(b*x + a)/b^3 + (b^12*c*d^5 - 25*a*
b^11*d^6)/(b^14*d^6)) - (5*b^13*c^2*d^4 + 14*a*b^12*c*d^5 - 163*a^2*b^11*d^6)/(b^14*d^6)) + 3*(5*b^14*c^3*d^3
+ 9*a*b^13*c^2*d^4 + 15*a^2*b^12*c*d^5 - 93*a^3*b^11*d^6)/(b^14*d^6))*sqrt(b*x + a) + 3*(5*b^4*c^4 + 4*a*b^3*c
^3*d + 6*a^2*b^2*c^2*d^2 + 20*a^3*b*c*d^3 - 35*a^4*d^4)*log(abs(-sqrt(b*d)*sqrt(b*x + a) + sqrt(b^2*c + (b*x +
a)*b*d - a*b*d)))/(sqrt(b*d)*b^2*d^3))*a^2*d*abs(b)/b^2 + 8*(sqrt(b^2*c + (b*x + a)*b*d - a*b*d)*(2*(4*(b*x +
a)*(6*(b*x + a)*(8*(b*x + a)/b^4 + (b^20*c*d^7 - 41*a*b^19*d^8)/(b^23*d^8)) - (7*b^21*c^2*d^6 + 26*a*b^20*c*d
^7 - 513*a^2*b^19*d^8)/(b^23*d^8)) + 5*(7*b^22*c^3*d^5 + 19*a*b^21*c^2*d^6 + 37*a^2*b^20*c*d^7 - 447*a^3*b^19*
d^8)/(b^23*d^8))*(b*x + a) - 15*(7*b^23*c^4*d^4 + 12*a*b^22*c^3*d^5 + 18*a^2*b^21*c^2*d^6 + 28*a^3*b^20*c*d^7
- 193*a^4*b^19*d^8)/(b^23*d^8))*sqrt(b*x + a) - 15*(7*b^5*c^5 + 5*a*b^4*c^4*d + 6*a^2*b^3*c^3*d^2 + 10*a^3*b^2
*c^2*d^3 + 35*a^4*b*c*d^4 - 63*a^5*d^5)*log(abs(-sqrt(b*d)*sqrt(b*x + a) + sqrt(b^2*c + (b*x + a)*b*d - a*b*d)
))/(sqrt(b*d)*b^3*d^4))*a*d*abs(b)/b)/b

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int x^2\,{\left (a+b\,x\right )}^{3/2}\,{\left (c+d\,x\right )}^{3/2} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*(a + b*x)^(3/2)*(c + d*x)^(3/2),x)

[Out]

int(x^2*(a + b*x)^(3/2)*(c + d*x)^(3/2), x)

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